A ball is projected vertically upwards from a tower of height 20m at a speed of 5m/s. Find:
1. Speed of the ball just before touching the ground.
2. Time taken to teach the ground.
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Speed just before reaching the ground = √u² + 2gh.
=> v = √u² + 2gh
=> v = √5² + 2(10)(20)
=> v = √(25 + 400)
=> v = √425
=> v ≈ 20.61 m/s
Total time taken = (u/g) [1 + √(1 + 2hg/u²)]
= (20/10) [1 + √(1 + 2*20*10/5²)]
= 2[1 + √(1 + 5/4)]
= 2[1 + 3/2]
= 5 sec
Proof for these formulae is given here:
https://brainly.in/question/41955450, you can derive from their and substitute the given values.
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