Question

A ball is projected vertically upwards. Its speed a
half of maximum height is 30 m/s. Maximum heigh
attained by the ball is
(1) 60 m
(2) 40 m
(3) 30 m
(4) 90 m
​

Answer 1

Answer:

feel free to ask if any confusion occurs...

Answer 2

90m would be the maximum height attained by the ball.

Explanation:

Given that,

u = 30 m/s

v = 0

g = -10 m/s^2

As we know,

v^2 = u^2 - 2gh

⇒ 0 = (30)^2 - 2 * (-10) * h

⇒ 20h = 900

⇒ h = 900/20

∵ h = 45

Since this height is half of the actual distance covered by the ball.

Thus,

The maximum height = 45 * 2

= 90 m

Learn more: Find the height

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