Question

A ball is projected vertically upwards. Its speed at half of maximum height is 20 m/s. The maximum height attained by it is [take g = 10 ms2]

Answer 1

Answer:-

= 40 m

Explanation:-

Given:-

Acceleration due to gravity = 10m/s

Final velocity at half distance = 20m/s

To Find:-

height = ?

??

Use equation of motion v²-u² = 2as

⇒ v²-u² = 2as

⇒ 20²-0² = 2 × 10m/s*s

⇒ 400 = 20m/s × s

⇒ s = 20 m

Half of maximum height = 20+20 = 40m

The maximum height attained by ball is 40 m.