A ball is projected vertically upwards with a velocity of 25 ms from the
bottom of a tower. A boy who is standing at the top of a tower is unable to
catch the ball when it passes him in the upward direction. But the ball again
reaches him after 3 sec when it is falling. Now the boy catches it then the
height of the tower is (g = 19 ms?)
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7
v²-u² as (I've attached the pic see above...!)
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2
Answer:
v^2-u^2 as shown above.
Explanation:
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