A ball is projected vertically upwards with speed u and
maximum height attained by it is h. The distance
travelled by it in last two seconds of its upward journey
will be lg = acceleration due to gravity]
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Explanation:
The formula for distance travelled in last nth second is,
S= 1/2*gt^2
Here, g= 10 m/s^2, t= 2 sec
S= 1/2* (10)(2)^2
S= 20 m
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