Question

A ball is projected vertically upwardward an velocity of u goes to a maximum height h before coming to ground. What is the value of h?

Answer 1

here,

g = 9.8 m/s.sq.

final velocity = o m/s

initial velocity = u m/s

now,

time,t = u/9.8 s

h = ut + 1/2at.sq.

  = u x u/9.8  +    1/2 x 9.8 x u/9.8

  = u^{2}/9.8  +  u/2

  = [2u^{2} + 9.8u]/19.6  

  = {u/19.6 x [2u + 9.8]} meter