Question

A ball is projected with 20 root 2 at angle 45 degrees with horizontal. The angular velocity of the particle at highest point of its journey about point of projection is/

Answer 1

Answer:

The angular velocity of the particle at highest point  is 1.38 rad/s.

Explanation:

Given that,

Velocity = 20√2

Angle = 45 °

We need to calculate the angular velocity

Using formula of angular velocity

$\omega=\dfrac{v}{r}$....(I)

We need to calculate the height

Using formula of height

$H_{max}=\dfrac{v^2\times\sin^2\theta}{2g}$

Put the value into the formula

$H_{max}=\dfrac{20^2\times2\times1}{2\times9.8\times2}$

$H_{max}=20.4\ m$

Put the value of H in equation (I)

$\omega=\dfrac{20\sqrt{2}}{20.4}$

$\omega=1.38\ rad/s$

Hence, The angular velocity of the particle at highest point  is 1.38 rad/s.

Answer 2

Explanation:

☢️PLEASE MARK AS BRAINLIEST ☢️