Question

a ball is projected with a velocity 20√3 m/ s making an angle 30 with the ground the time interval after which the velocity vector will make an angle 30 t to the horizontal​

Answer 1

Answer:

hope it will help you....

Answer 2

Answer:

The time is 2 sec.

Explanation:

Given that,

Velocity $v= 20\sqrt{3}$

Angle = 30°

We need to calculate the time

Using formula of angle

$\tan\theta=\dfrac{v_{y}}{v_{x}}$

Using equation of motion

$\tan\theta=\dfrac{u_{y}-gt}{u_{x}}$

Put the value into the formula

$\tan30=\dfrac{20\sqrt{3}\sin60-10t}{20\sqrt{3}\cos60}$

$\dfrac{1}{\sqrt{3}}=\dfrac{20\sqrt{3}\times\dfrac{\sqrt{3}}{2}-10t}{20\sqrt{3}\times\dfrac{1}{2}}$

$\dfrac{1}{\sqrt{3}}=\dfrac{30-10t}{10\sqrt{3}}$

$10=30-10t$

$t=2\ sec$

Hence, The time is 2 sec.