Question

A ball is projected with a velocity of 20 m/s vertically. Find the distance travelled in first two second. (use g = 10m/sec) (a) 20 m n. 10​

Answer 1

Explanation:

20will be ans

for more just thanks me

Answer 2

Given :

Initial velocity 'u' = 20m/s

Acceleration due to gravity 'g' = 10m/$s^{2}$

To find :

Distance 's' traveled by the projected ball in 2s.

Solution :

We know the equation of motion for a distance 's', acceleration 'a', time 't', and initial velocity 'u'.

            s = ut + (1/2)a$t^{2}$

Here, a = g = 10m/$s^{2}$

          u = -20m/s , since the ball is projected upwards.

           t = 2s

Therefore, s = [(-20m/s) x 2s] + [(1/2) x 10m/$s^{2}$ x (2s$)^{2}$]

                    = -40m + 20m

                  s = -20m , where neagtive sign indicates the  

                                     upward motion of the ball.

Thus, the projected ball travels a distance of 20m in the first two seconds.