Question

a ball is projected with a velocity of 30ms at an angle of 60deg to the horizontal point
​

Answer 1

Answer:

2s

Explanation:

Given : u=20

3

m/s θ=60

o

Horizontal component of velocity initially u

x

=u cos60=20

3

×

2

1

=10

3

m/s

Since, there is no acceleration in horizontal direction. So horizontal component of velocity remains the same all the time.

Final horizontal component of velocity v

x

=u

x

=10

3

m/s

Final velocity makes an angle 30

o

with horizontal.

So, vertical component of final velocity v

y

=u

x

tan30=10

3

×

3

1

=10

Initial vertical comonent of velocity u

y

=usin60=20

3

×

2

3

=30 m/s

Using v

y

=u

y

−gt

∴ 10=30−10t

⟹ t=2 s