Question

a ball is projected with horizontal velocity v0=root9gR at the bottom most point attached with the inextensible string length r and fixed at o as shown tension in the string in horizontal position​

Answer 1

Answer:

7mg

Explanation:

v square =v not square -2gR(1-cos theta)

Answer 2

Answer:

A ball is projected with horizontal velocity $v_{o}$= $\sqrt{9gR}$

The bottom-most point is attached with the inextensible string length R and fixed at O.

Solution:

Formula: $v^{2} = v^{2} _{o} -2gR(1-cos\theta)$

              $v^{2} = 7gR+2gRcos\theta$

              $T-mgcos\theta=\frac{mv^{2} }{R}$

             $v_{h} = \sqrt{7gR}$

             $T=7mg$