Question

A ball is projected with kinetic energy e at an angle 45 degree with the horizontal its kinetic energy at the highest point will be

Answer 1

Let the initial velocity with which the ball was projected be v m/s.

Therefore,

Check this attachment :-)

Answer 2

Hey !

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Kinetic energy = 1/ 2 mv^2

Velocity will be v cos 45

Kinetic energy at highest point :-

1 / 2 m ( v cos 45) ^2

1 / 2 m v ^2 (1 / 2)

1 / 2 E

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