Question

A ball is projected with kinetic energy E at an angle if 45 to the horizontal at the highest point of it's time of flight potential energy is

Answer 1

Answer:

Potential energy at highest point is E/2

Explanation:

At the highest point of the projectile the velocity of the ball will be vcosθ

= vcos45° = v/√2

KE =1/2 mv^2 = E

At highest point the

KE =1/2 m(v/√2) ^2 = E/2

Using conservation of energy the rest E/2 goes as PE