Question

A ball is projected with kinetic energy E at angle of 45 to the horizontal. At the highest point during its flight, its kinetic energy will be ?

Answer 1

hola mate hope it helps you

Given:

let v be initial velocity.

K.E= E =1/2 mV²

VELOCITY OF PARTICLE AT HIGHEST POINT = vcos 45

kinetic energy of particle at highest point is =1/2 m(vcos45)²

=1/2(mv²)(1/2)

=1/2 E

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