Question

A ball is projected with speed u at an angle THETA to the horizontal.
The range R of the projectile is given by R=u^2*sin2THETA/g for which value of angle THETA will the range be maximum for a given speed of projection ?
given (Here g = constant)
1.60
2.45
3.90
4.30
find the answer with explantation

Answer 1

Dear mate value of horizontal range is always max. for 45 degrees angle

as Sin2A = 2 (SinA CosA)

which is max. for 45 degrees..

u can verify by doing it.....

Best of Luck..✌