Question

A ball is projected with velocity 10m/s at angle 30° with horizontal surface .the range of the projectil?

Answer 1

First break the velocity into components:
$v_{x}=10cos30=[tex] v_{x}.t= 5 \sqrt{3}.1=5 \sqrt{3} m$ [/tex]
$v_{y}= 10sin30=5$

Now calculate time after which the projectile will hit the ground, this means that displacement in y will become 0.

0=5t$- \frac{1}{2}10. t^{2}$
$5t=5$
t=1 seconds

Now,
 Range=