Question

A ball is projected with velocity 19.6 metre per second find the time interval needed to rise up to the top most position​

Answer 1

Answer:

2sec

Explanation:

u=19.6

v=u+at

v=0

therfore 0=u-gt

-u=-gt

t=(u/g)

19.6/9.8

2 sec

Answer 2

Answer:-

t = 1.96 s

Given :-

u = 19.6 m/s

g = 10 m/s²

v = 0 m/s

To find :-

Time interval to reach the maximum height.

Solution:-

Time of ascend → The time taken by a projected body to reach its maximum height is known as time of ascend.

By using equation of motion,

→$\mathsf{v = u-gt}$

→$\mathsf{0 = 19.6 - 10\times t}$

→$\mathsf{ -19.6 =-10t}$

→$\mathsf{t = \dfrac{-19.6}{-10}}$

→$\mathsf{t = \dfrac{196}{100}}$

→$\mathsf{ t = 1.96 s }$

hence,

The time taken to reach the maximum height will be 1.96s.

• Shortcut formula :-

$\huge \boxed{t =\dfrac{u}{g}}$