Question

A ball is projected with velocity u at an angle alpha with horizontal plane.Its speed when it is projecting with angle beta

Answer 1

ux=ucos(alpha)

uy=usin(alpha)

when angle =beta.

vx=vcos(beta) that must be equal to ux=ucos(alpha)

so

vcos(beta)=ucos(alpha)

v=ucos(alpha)/cos(beta)

Answer 2

Explanation:

ux =→ucos alpha

uy=→u sin alpha

angle =→ beta

vx=ux

.•.hence,

vcosbeta = u cos alpha

v = u cos alpha /ucos beta