Question

A ball is projected with vwlocity 50ms-1.Then the speed at half of the maximum height {g=10ms}
a) 100ms-1
b) 125ms-1
c)35ms-1
d)45-1

Answer 1

Answer:

b) 125ms-1 is the answers.

Explanation:

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Answer 2

Explanation:

u=50m/s

v=0m/s

a(-g)=-10m/s²

s=?

2as=v²-u²

2as=0-50²

2×-10×s=-2500

s=-2500/-20

s=125 m

in half of the maximum height =125/2

so 2as = v²-u²

2× -10×125/2=0-u²

-1250=-u²

u=√1250

u=35.35

So the answer is 35 m/s