Question

A ball is projectile fired with 60° angle from tower peak. Then vertex component of velocity

Answer 1

Answer:

usin60*=u root3/2**********

Answer 2

Answer:

Hey mate your answer is

Explanation:

${v}^{2} y = {( - u \sin60 \:})^{2} + 2hg$

${v}^{2} y = {( - u \times \sqrt{3 } \div 2) }^{2} + 2hg$

${v}^{2}y = - {u}^{2} \times \frac{3}{4} + 2hg$

${v}^{2} y = \frac{ - 3 {u}^{2} }{4} + 2hg$

Hope this will help uh!

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