Question

A ball is released from 10 m. If after the impaft ball loses 40% energy then ball rises upto

Answer 1

Answer:

Explanation:let the mass of the ball be "m"

h₁ = initial height before bounce for the ball = 10 m

initial potential energy before bounce is given as

PE₁ = mg h₁

h₂ = final height after bounce for the ball = ?

final potential energy after bounce is given as

PE₂ = mg h₂

Using conservation of energy

PE₂ = 60% of PE₁ (Since remaining 40% energy is lost)

mg h₂ = 0.60 mg h₁

h₂ = (0.60) (10)

h₂ = 6 m

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