A ball is released from a certain height and reaches the ground in 2 seconds assuming g is equal to 10 m/s2 calculate the speed of the ball on reaching the ground and the height from which the ball is released
Answers
Answered by
1
Answer:
Explanation:
u = 0
a = 9.8 m/s²
t = 3s
h = ?
v = ?
h = ut + 0.5at²
= 0*3 + 0.5*9.8*3²
= 0 + 44.1
= 44.1 m
v = u + at
= 0 + 9.8*3
= 29.4 m/s
Height = 44.1m
Velocity = 29.4 m/s
Answered by
2
Answer:
Explanation:
u = 0 a = 9.8 m/s² t = 3s
h = ? v = ?
- h = ut + 0.5at²
= 0.5*9.8*3² (since u is zero )
= 44.1m
Height = 44.1m
- v = at ( since u is zero)
= 9.8*3
= 29.4 m/s
Velocity = 29.4 m/s
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