A ball is released from a height of 1m what time it will take to reach the surface of the earth
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s = ut + (1/2)at^2
as the ball is released from rest u is 0 as ball is not moving intitially
s= (1/2)at^2
a = g = 9.8m/s^2
s = 1 (given)
t^2 = (2*s)/a
t=0.452 seconds
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Hope both methods will help you.
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