A ball is released from a height of 1metre. What time it will take to reach the surface of the earth
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Answer:s = ut + (1/2)at^2
as the ball is released from rest u is 0 as ball is not moving intitially
s= (1/2)at^2
a = g = 9.8m/s^2
s = 1 (given)
t^2 = (2*s)/a
t=0.452 seconds
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Explanation:
under root 1/5
hope this will helpful
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