a ball is released from a height of 20m hits the ground and rebounds to a height of 16m the percentage loss of energy during collision is?
Answers
Answered by
64
The percentage of the lose of energy can be calculated as under:
Initial height of the ball = 20 m
Final height of the ball = 16 m
Initial Energy of the ball = m*g*h = 20*mg
Final Energy of the ball = m*g*h = 16*mg
Loss of Energy = 4*mg
Percentage loss = 4/20 * 100
Percentage loss = 20 %
Answered by
9
Answer:
20%
Explanation:
The percentage of the lose of energy can be calculated as under:
Initial height of the ball = 20 m
Final height of the ball = 16 m
Initial Energy of the ball = m*g*h = 20*mg
Final Energy of the ball = m*g*h = 16*mg
Loss of Energy = 4*mg
% loss = 4/20 * 100%
=20%
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