Question

A ball is released from a roof 40 m high. Calculate the velocity of the ball when it just reaches the ground.
take g=10(m/s²)​

Answer 1

Answer:

"The total height of the tower is 40 m.

Lets total time be = t

Initial velocity u= 0

Case 1: whats the velocity when the body at 20 m. High

From the formula

V^2 - u^2 =2 * a* s

V^2 - 0^2 = 2*9.81* 20

V^2 = 392.4

V= √392.4

V = 19.809 m/s

Case2 :velocity when the ball hits the ground

From

V^2 - u^2 =2 * a* s

V^2 - 0^2 = 2 *9.81* 40

V^2 = 784.8

V=√784.8

V = 28.01 m/s "

Answer 2

Answer:

What is the velocity of an object thrown upwards at a speed of 40 ms 1 after 2 sec G 10 ms 2?

What is the velocity of an object thrown upwards at a speed of 40 ms 1 after 2 sec G 10 ms 2?The Correct Answer is Option 3 i.e 60 m. Initial velocity (u) is given as 40 m/s. When a ball is thrown vertically upwards acceleration due to gravity is to be taken negative i.e a = - g = -10 m/s2.