Question

a ball is released from aheight and it reaches the ground in 3s.if g=9.8m/s2,find the height from which the ball was released and the velocity with which the ball will strike the ground.

Answer 1

u = 0
a = 9.8 m/s²
t = 3s
h = ?
v = ?

h = ut + 0.5at²
   = 0*3 + 0.5*9.8*3²
   = 0 + 44.1
   = 44.1 m

v = u + at
  = 0 + 9.8*3
  = 29.4 m/s

Height = 44.1m
Velocity = 29.4 m/s

Answer 2

Answer:

u = 0

a = 9.8 m/s2

t = 3s

h = ?

v=?

h = ut + 0.5at?

= 0*3 + 0.5*9.8*32

= 0 + 44.1

= 44.1 m

v = u + at

= 0 + 9.8*3

= 29.4 m/s

Height = 44.1m Velocity = 29.4 m/s