A ball is released from certain height it loses 50% of its kinetic energy on
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As the question us incomplete , still I will try.
Since it loses 50 % of its kinetic energy on striking ground, its PE is also reduced by half.
Therefore The height attained =1/2 of initial height.
I guess this is what u wanted to ask.
Thanks .
Since it loses 50 % of its kinetic energy on striking ground, its PE is also reduced by half.
Therefore The height attained =1/2 of initial height.
I guess this is what u wanted to ask.
Thanks .
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