a ball is released from height above the ground find its velocity after 5secs take g=10ms-1
Answers
Answered by
4
v = u + at
v = 0 + 10 × 5
v = 0+50
v = 50 m/s
v = 0 + 10 × 5
v = 0+50
v = 50 m/s
Answered by
2
U =0m/s
t=5sec
a=10m/s^2
by using
v=u+at
v=0+(10×5)
v= 50m/s
t=5sec
a=10m/s^2
by using
v=u+at
v=0+(10×5)
v= 50m/s
Similar questions
Math,
8 months ago
Social Sciences,
8 months ago
Physics,
1 year ago
Math,
1 year ago
Geography,
1 year ago