Physics, asked by aliyuabdullahi12, 1 year ago

a ball is released from height above the ground find its velocity after 5secs take g=10ms-1

Answers

Answered by Hazel11
4
v = u + at
v = 0 + 10 × 5
v = 0+50
v = 50 m/s
Answered by Diya208
2
U =0m/s
t=5sec
a=10m/s^2
by using
v=u+at
v=0+(10×5)
v= 50m/s
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