Physics, asked by honey27khan, 8 months ago

A ball is released from height and it reaches
the ground in 4 sec. If g=9.8 m/s2, find the height
from which the ball was released

Answers

Answered by yashikakhandelwal15
1

Answer:

78.4m

Explanation:

s= ut+1/2at^2

h=ut+ 1/2gt^2

u=0( because ball is released)

h= 0+.5*9.8*4*4

h=78.4m

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