Question

A ball is released from height h and another from 2 has the ratio of time taken by the two balls to reach ground is

Answer 1

According to formula

s=ut +1/2at^2

in this case u=0

and a=g

therefore

for ball 1 :- h=1/2gt1^2

for ball 2 :- 2h=1/2gt2^2

therefore dividing eqn 1 by 2 we get

1/2=t1^2/t2^2

therefore t1/t2=1/√2

or the ratio is 1:√2

therefore a is the correct answer.

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