Question

A ball is released from height of 1metre.what time it will reach the surface

Answer 1

please refer to the pic for the answer

Answer 2

$s \: = ut \: + \: 1 \div 2 \: a {t}^{2}$
1 = 0*t + 1/2 * 9.8 t^2.
1 = 1/2 * 9.8 t^2.
t^2 = 9.8 / 2.
t = √4.9 seconds.