a ball is released from rest and rolls down an inclined plane, requiring 4s to cover a distance of 100 cm. a.) what is its acceleration in cm/s2?
b.) how many centimeters would it have fallen vertically in the same time.
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Explanation:
a) Let the acceleration of the ball be a cm/s²
Applying equations of motion,
S = ut + 1/2×at²
=> 100cm = 1/2 × a × 4²
=> a = 100/8 = 12.5 cm/s²
b) For vertical fall,
a = g= 10 m/s²
S =1/2 × 10 × 4² = 80 m = 8000 cm
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Answer:
A. Acceleration
a=2d/t²
a=2(100)/4²
a=12.5
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