Question

A ball is released from the height of 100m.At the same time another ball is thrown vertically upward with velocity 25m/s. Find when and where the 2 balls will meet ?

Answer 1

Lets take distance covered by the stone thrown upwards to meet the other as x. Then the other stone covers a distance of (100-x)m.

Let the ball dropped down be b1. So the ball thrown up is b2..........
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....see picture!!!!!...

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hence...
Balls meet each other at the height of 78.4 metres from the top of tower or 21.6metres above the ground after 4 seconds.....
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