a ball is released from the height of 1metre ?what time it will take to reach the surface sorry for asking again n again but my exam is starting tmrw soo Plex help me
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u =0
s=1 m
a=g= 10 m/ssquare
t=?
s=ut+1/2at square
s=1/2×10×t^2
1=5t^2
1/5=t^2
t^2= 0.2
t= underoot1/5 seconds
s=1 m
a=g= 10 m/ssquare
t=?
s=ut+1/2at square
s=1/2×10×t^2
1=5t^2
1/5=t^2
t^2= 0.2
t= underoot1/5 seconds
Sangaychodenlepcha:
tysm soo much
wc
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