Question

A ball is released from the top of a tower from a height 'h'm. It takes T seconds to reach the ground. What is the position of the ball at T/3 second​

Answer 1

Explanation:

Sorry

No idea about this

the values are not given properly

hope it helps u

follow me

Answer 2

Let the acceleration be 'g'

Then initial velocity = 0 m/s [in T seconds]

Let the distance be 'h' m.

We know,

Equation of motion:

s = ut + 1/2 gT²

Then,

h = 1/2gT² ......(1)

h1 = 1/2gT²/9'......(2)

Substitute (1) and (2):

We'll get h1 = h9

∴ The distance from ground is h-h/9 = 8h/9 ←(ANSWER)

Please mark as Brainliest