Question

A ball is released from the top of a tower of h metres height . It takes T seconds to reach the ground .what is the position of the ball in T/3 seconds.

Answer 1

heya......



Let the acceleration be 'g'

Then initial velocity = 0 m/s [in T seconds]

Let the distance be 'h' m.


We know,

Equation of motion:


s = ut + 1/2 gT²

Then,

h = 1/2gT² ......(1)

h1 = 1/2gT²/9'......(2)


Substitute (1) and (2):


We'll get h1 = h9


∴ The distance from ground is h-h/9 = 8h/9 ←(Answer)




tysm.#gozmit

Answer 2

Answer:

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Hope it will be helpful :)