Question

A ball is released from the top of a tower of height 20 m with the acceleration of 10 m/s^2. Its final velocity just before touching the ground is

Answer 1

Explanation:

u=0m/s

a=10m/s^2

s=20m

2as=v^2-u^2

=)2×10m/s^2×20m=v^2-0m^2/s^2

=)400m^2/s^2=v^2

=)v=√400m^2/s^2

=)v=20m/s

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