Question

A ball is released from the top of a tower. The ratio of work done by force of gravity in
first, second and third second of the motion of the ball is:-

Answer 1

Answer:

1:3:5

Explanation:

When ball is released from the top of a tower, then the ratio of distances covered by the ball in first, second and third second is

H

I

:H

II

:H

III

=1:3:5 [because h

n

∝(2n−1)]

∴ Ratio of work done

mgh

I

:mgh

II

:mgh

III

=1:3:5.