Question

A ball is released from the top of the tower. The ratio of work done by force of gravity in first secobd and third second

Answer 1

Answer:1:5

Explanation:wD= force * displacement

Displacement in nth second is given by Snt=u+a/2(2n-1)

Mg(a/2(2(1)-1)) : Mg(a/1(2*3)-1))

1:5