Question

a ball is released from the top of tower of height h meter.it takes T second to reach the ground. where is the ball at the time T/2 sec

Answer 1

Answer:25% of the total hight from above

Answer 2

Answer:

Lets take the height as H.

Formula for H is ,

H = gt²/2            [ from S = ut+1/2at² ]

now we will take the unknown height as h , and time as t/2

By applying the same formula we get ,

h = g(t/2)² / 2

  = gt²/8

After obtaining the result , we compare H and h in the form of ratio.

H : h = gt²/2  :  gt²/8

        = 1/2 : 1/8

         = 4/1

It means that at t/2 , the ball will be at H/4 .

hope it helped and please mark as brainliest:)