A ball is released from the top of tower of height hmeter. it take t second to reach the ground .what is the position of ballin t/3 second?
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Answer:
8h/9 from ground
Explanation:
If we assume the total height to be H
H=0+1/2at^2
So we will assume the situation if the ball is dropped from a height h and time taken is t and also acceleration is g
By applying Newtons 2 nd equation
h=ut +1/2at^2
u=0 as the ball is dropped from rest
substituting the values
h=0+1/2 a T^2/9
On Comparing the values
we get height h/9 from the top and also 8h/9 form the ground.
OR{Trick}
We know that h is directly propotinal to the square of time so height becomes propotional to t^2/9 giving us height to be h/9
and height from ground 8h/9
Hope it Helps!!!
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