Question

A ball is released from the top to a tower .The ratio of workdone by force of gravity in 1 st

Answer 1

$work = force \times displacement \times \sin(x)$
let height of the tower be= h
mass of the ball be=m
then force of gravity on it= m×g×)
as displacement and gravity are in the same direction sin(x) = sin(90°) = 1
thus, work = m×g×h