A ball is released from top of a tower of height h meters.it takes t seconds to reach the ground .what is the position of the ball in t/3 seconds
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By the formula ,
s = ut + (1/2) at2
by replacing the values,
H = 0(T) + (1/2) (10) (T2)
H = 5T2
.
Therefore,
Position of the ball at T/3 secs = (1/2) (10)(T/3)2
=5T2 / 9 = H/9
.
Hence at T/3 secs the ball is H/9 meters from top of the tower.
Hope it's help you
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s = ut + (1/2) at2
by replacing the values,
H = 0(T) + (1/2) (10) (T2)
H = 5T2
.
Therefore,
Position of the ball at T/3 secs = (1/2) (10)(T/3)2
=5T2 / 9 = H/9
.
Hence at T/3 secs the ball is H/9 meters from top of the tower.
Hope it's help you
Please mark me in brain list answer
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