Question

A ball is rolled at a velocity of 12 m/sec. After 36 seconds, it comes to a stop. What is the acceleration of the ball?
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Answer 1

GIVEn

A ball is rolled at a velocity of 12 m/sec. After 36 seconds, it comes to a stop.

TO FINd

What is the acceleration of the ball?

SOLUTIOn

Apply this formula to solve this question

$\Large{\boxed{\bf{a=\dfrac{v-u}{t}}}}$

where ,

a = acceleration

v = final velocity

u = initial velocity

t = time taken

• v = 0
• u = 12m/s
• t = 36sec
• a = ?

$\implies\tt a=\dfrac{v-u}{t} \\ \\ \implies\tt a=\dfrac{0-12}{36} \\ \\ \implies\tt a=\cancel\dfrac{-12}{36} \\ \\ \implies\tt a=-0.3m/s^2$

Here, (-) minus shows retardation

Answer 2

$\huge{\underline{\underline{\mathrm{\blue{GIVEN:-}}}}}$

• Initial Velocity(u) of ball = 12 m/s
• Final Velocity(v) of ball = 0 [Since, the ball has stopped]
• Time taken by a ball = 36 Sec

$\huge{\underline{\underline{\mathrm{\blue{TO\:FIND:-}}}}}$

Find the acceleration (a) of the ball = ?

$\huge{\underline{\underline{\mathrm{\blue{FORMULA\:USED:-}}}}}$

$\large{\boxed{\bf{\green{a = \frac{v-u}{t}}}}}$

$\huge{\underline{\underline{\mathrm{\blue{SOLUTION:-}}}}}$

 ➭ We have given that, a ball is rolled at a velocity of 12 m/sec. After 36 seconds, it comes to a stop

《We have to find the acceleration of the ball》 

✒ On putting the values in the formula, we get

$\implies$$\large\bf\green{a = \frac{v-u}{t}}$

$\implies$$\bf{a = \large\frac{0-12}{36}}$

$\implies$$\bf{a =\large \cancel{\frac{-12}{36}}}$

$\implies$$\large\bf\red{a = -0.34\: m/{s}^{2}}$

$\huge{\underline{\underline{\mathrm{\blue{FINAL\: ANSWER:-}}}}}$

$\huge{\boxed{\boxed{\bf{\red{a = 0.34\: m/{s}^{2}}}}}}$