Question

A ball is rolled at a velocity of 12m/sec. After 36secs,it comes to a stop . What is a acceleration of the ball??

Appropriate answer please..​

Answer 1

Refer to attached Image ❤️

$\huge\pink{\mathfrak{answer}}$

ie taninv(dv/dt) since it is linear taninv(12/33)= 0.33 m/s^2 deceleration. If in case the velocity doesn't follow the linear path acceleration= d(velocity profile)/dt. ie the first order differentiation of velocity is the acceleration.