A ball is rolled off along the edge of a horizontal table with a velocity 4 ms-1 .It hits the ground after 0.4s.Then (g=10ms-1
The height of the table is
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Answer:
u=4m/s
t=0.4s
h=S
a=g=10m/s^2
From 2nd equation of Kinematics
S=ut+1/2gt^2
S=4×0.4+1/2(10×0.4×0.4)
S=1.6+1/2(1.6)
S=1.6+0.8
S=2.4m
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