Physics, asked by sarithakalithkar1976, 1 day ago

A ball is rolled off along the edge of a horizontal table with a velocity 4 ms-1 .It hits the ground after 0.4s.Then (g=10ms-1

The height of the table is

Answers

Answered by anujaanantpatil
0

please make me brainleist

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Answered by TonySama009
0

Answer:

u=4m/s

t=0.4s

h=S

a=g=10m/s^2

From 2nd equation of Kinematics

S=ut+1/2gt^2

S=4×0.4+1/2(10×0.4×0.4)

S=1.6+1/2(1.6)

S=1.6+0.8

S=2.4m

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