A ball is rolled off the edge of a dining table 1.5 m high with a horizontal velocity of 2.2 m/s. With what velocity does it strike the ground? How far from the edge of the table does it land on the floor?
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Answer:
t = sqrt(2*1.5/9.8)
x = 2.2t
for velocity
vx is constant at 2.2
vy = 9.8t
Use Pythagorean to find total v
Explanation:
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