Question

a ball is rolling down a place and comes to rest after 30 seconds. If the initial velocity is 10m/s^2 what is the acceleration?

Answer 1

Answer:

v=0m/s

u=10m/s

t=30s

a=(v-u)/t=0-10/30=-1/3=--0.333333m/s^2

Explanation:

Answer 2

Answer:

v=0 because it comes to rest

t=30

u=10

a=v-u/t

a=0-10/30

a=-10/30

a=-1/3ms^-2