a ball is selected at random from a bag containing 3 red balls,4 black balls and 5 green balls. the first ball is replaced and a second is selected.find the probability of obtaining: a) two red balls b)two green balls
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Answered by
12
Answer:
P(two red balls) = 3/12 = 1/4
P(two green balls) = 5/12
Answered by
1
Answer:
a = 2÷ 3+ 4+5
= 2÷12
=1/6
b = 1/6
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